2x/x^2-9=6/x^2-9-4/x+3

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Solution for 2x/x^2-9=6/x^2-9-4/x+3 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

(2*x)/(x^2)-9 = 6/(x^2)-(4/x)-9+3 // - 6/(x^2)-(4/x)-9+3

(2*x)/(x^2)+4/x-(6/(x^2))-9-3+9 = 0

(2*x)/(x^2)+4/x-6*x^-2-9-3+9 = 0

6*x^-1-6*x^-2-3 = 0

t_1 = x^-1

6*t_1^1-6*t_1^2-3 = 0

6*t_1-6*t_1^2-3 = 0

DELTA = 6^2-(-6*(-3)*4)

DELTA = -36

DELTA < 0

x belongs to the empty set

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